Brahmagupta's solution to a quadratic equation of the form ax2 + bx = c involved only one solution. Which solution would he have found for the equation 3x2 + 4x = 6?
O x= 4(3)(6) + 42 - 4
2 (3)
222-4 22-2
3
6
O x = 4(3)(4) + 62 - 6 _ 2/21-6
21-3
3
2 (3)
6
O x= V4(4)(6) + 32 - 3
V105 - 3
8
2(4)
O x = 4(3)(6) - 42 + 4
214 + 4
6
14+2
3
2 (3)

75 tickets have been sold so far.

step-by-step explanation:

in this question it is clearly mentioned that 45 children's tickets have been sold and this number is 60% of the total tickets sold.

now let's assume the total number of tickets sold be x.

then 60% of x = 45

⇒

⇒ x(.6) = 45

by dividing with .6 on both the sides of the equation

⇒ x = 75

therefore 75 tickets have been sold so far.

your answer is 228

step-by-step explanation:

add the top and bottom bases together, then divide them by 2, then multiply by the height.