Two cars travel at the same speed to different destinations. Car A reaches its destination in 25 minutes. Car B reaches its destination in 35 minutes. Car B travels 4 miles farther than Car A. How fast do the cars travel?

We are given that speed of car A is equal to speed of car B.

Step-by-step explanation:

We are given that speed of car A is equal to speed of car B.

Also let car A travels x miles.

and car B travels y miles.

Car A reaches its destination in 17 minutes.

this means that speed of car A is given by: \dfrac{x}{17}

17

x

miles/minutes ( since speed is defined as the ratio of distance and time).

Car B reaches its destination in 32 minutes.

This means that the speed of car B is given by: \dfrac{y}{32}

32

y

miles/minutesas speed of both cars are equal this means:

\dfrac{x}{17}=\dfrac{y}{32}

17

x

=

32

y

(1)

Also we are given Car B travels 12 miles farther than Car A.

this means y-x=12y−x=12

y=12+xy=12+x (2)

on using equation (1) and (2) we have:

\begin{gathered}\dfrac{x}{17}=\dfrac{12+x}{32}\\ \\32x=17(12+x)32x=17\times12+17x32x-17x=17\times1215x=122\times17x=13.6\end{gathered}

17

x

=

32

12+x

32x=17(12+x)

32x=17×12+17x

32x−17x=17×12

15x=122×17

x=13.6

32x=17(12+x)

32x=17×12+17x

32x−17x=17×12

15x=122×17

x=13.6

Hence the speed of car A is 0.8 miles/minutes ( since x/17 is the speed of car A)

Speed of car B=0.8 miles/minutes.

as speed o

range =5

step-by-step explanation:

to find the range, we take the largest value and subtract the smallest value.

the largest value is 5

the smallest value is 0

the range is 5-0   =5