The height in meters, S, of a rocket t seconds after being launched with an upward velocity of 80 meters per second may be approximated by this equation: S = 80t - 5t^2
How many seconds after launch is the rocket first 140 meters above the ground?
A. 14
B. 5.3
C. 8
D. 2

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Consider this equation. |y + 6| = 2 what can be concluded of the equation? check all that apply. there will be one solution. there will be two solutions. the solution to –(y + 6) = 2 will be also be a solution to the given absolute value equation. the solution(s) will be the number(s) on the number line 2 units away from –6. the value of y must be positive since the variable is inside absolute value signs.