A paint manufacturer wants to determine the average drying time of a new interior wall paint. For n = 50 test areas of equal size he obtained a sample mean drying time of ¯x = 63.3 minutes and a sample standard deviation of s = 8.4 minutes. (a) (5 points) Construct the 95% confidence interval for the true mean µ. (b) (5 points) Suppose the population has a normal distribution, construct the exactly 95% confidence interval for the true mean µ. (c) (5 points) Suppose the population has a normal distribution, construct the 95% prediction interval for a new observation.

a) the 95% confidence interval for the true mean µ is 60.971, 65.629

The exact 95% confidence interval for the true mean µ is 60.971, 65.629

P (x`- ∝ s/√n<u <x`+ ∝ s/√n) = 0.95

Step-by-step explanation:

n= 50

x`= 63.3

s= 8.4 minutes

∝= 95%= ±1.96

The formula for calculating the confidence interval is:

x`± ∝ s/√n

Putting the values

x`± 1.96 s/√n

63.3 ± 1.96(8.4/√50)

63.3± 2.3287

60.971, 65.629

a) the 95% confidence interval for the true mean µ is 60.971, 65.629

b) Putting the values

x`± 1.96 s/√n

63.3 ± 1.96(8.4/√50)

63.3± 2.3287

The exact 95% confidence interval for the true mean µ is 60.971, 65.629

c) The prediction level tells that the drying time of the wall from 60.971 to 65.629 minutes must be in the range 95 % of the time.

And is given by

P (x`- ∝ s/√n<u <x`+ ∝ s/√n) = 0.95

5 x 14?

im new, sorry if this is wrong.

step-by-step explanation:

30005

yes ok