In the cube shown below, the distance between vertices 2 and 6 is 15 cm. If the cube is divided into two equal parts by a plane parallel to the face defined by vertices 2, 3, 6, and 7, what will be the area of the cross-section?
A.
45 sq cm
B.
15 sq cm
C.
225 sq cm
D.
60 sq cm

256 sq cm

Step-by-step explanation:

cube is a three-dimensional figure with six congruent square faces. Since each face is congruent, each of the edges have the same length.

The cross-section described is shown below.

The cross-section is also a square which is congruent to the other faces of the cubes. Therefore, the edges of the cross-section will each measure 16 cm. Find the area by using the formula for the area.

         A=lw

             =(16cm) (16cm)

                =256 sq cm  

So, the area of the cross-section is 256 sq cm.

hope this helps some wayStep-by-step explanation:

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq

these sign is used to tell weather the number is greater or less than the number   <   or >     but this sign means its equal =    

hope this you and

step-by-step explanation: