Solve the following system of equations: x + 3y = 10 and 2x + 2y = 12

x=4 and y=2

Step-by-step explanation: Step 1: Solve x+3y=10 for x:

x+3y=10

x+3y+−3y=10+−3y(Add -3y to both sides)

x=−3y+10

Step 2: Substitute−3y+10for x in2x+2y=12:

2x+2y=12

2(−3y+10)+2y=12

−4y+20=12(Simplify both sides of the equation)

−4y+20+−20=12+−20(Add -20 to both sides)

−4y=−8

−4y

−4

=

−8

−4

(Divide both sides by -4)

y=2

Step 3: Substitute 2 for y in x=−3y+10:

x=−3y+10

x=(−3)(2)+10

x=4(Simplify both sides of the equation)

So your answer would be x=4 and y=2

Hope this helps

i am thinking c. sorry if im wrong .

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