Mathematics, 29.03.2021 21:10 williamwu2750
The function f is continuous where f(β5) = β1 and f(5) = 6, and g is a function defined by g(x) = 1 β (f(x))2. Is there a value c for β5 < c < 5 such that g(c) = 1? Why, or why not?
A) Yes; the function g is continuous
B) Yes; g(β5) < 1 < g(5), so IVT guarantees there is a value c for β5 < c < 5 such that g(c) = 1
C) No; 1 is not between g(β5) and g(5), so IVT cannot guarantee there is a value c for β5 < c < 5 such that g(c) = 1
D No; the function g is not continuous
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The function f is continuous where f(β5) = β1 and f(5) = 6, and g is a function defined by g(x) = 1...
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