The graph of a cosine function is shown. Which two points on the midline of the function are separated by a distance of one period?

(pi/8, 1) and (5*pi/8, 1)

Step-by-step explanation:

First, the midline is a horizontal line that cuts the graph in two halves.

In this case, we can see that the maximum of the function is y = 2.5, and the minimum is y = -0.5

The difference is:

Diff = (2.5 - (-0.5)) = 3

If we subtract half of the difference (3/2 = 1.5) to the maximum, we get the midline.

Then:

midline: y = 2.5 - (3/2) = 1

the midline is the line y = 1

Now, a period T is such that:

Sin(x) = Sin(x + T)

Two points that are in the midline and that are separated by a period will be two points on the line y = 1, and that are in corresponding parts of the graph.

Here the two points are, counting from left to right, the third and the 11th.

(both of them are in the line y = -1 and in the negative slope part).

The points are:

(pi/8, 1) and (5*pi/8, 1)

answer: the four apples you took away.

step-by-step explanation:

let's fu(!

step-by-step explanation: