The length of a rectangle is 1 foot more than twice the width. The area is 55 square feet. Find the length of the dimension of the rectangle.

11 ft

Step-by-step explanation:

The formula for the area of a rectangle of length L and width W is

A = L * W.  

Represent the length, L, by 2W + 1 ("1 more than twice the width").  Then the area formula (above) becomes:

A = 55 ft^2 = (2W + 1)(W), which, when simplified, results in:

2W^2 + W - 55 = 0, whose coefficients are {2, 1, -55}.  Let's use the quadratic formula to solve this for W:

The discriminant, b^2 - 4ac, is 1^2 - 4(2)(-55), or 441.  The square root of 441 is 21.  Thus, the quadratic formula gives us:

        -1 ± 21

W = = (1/4)(-1 + 21), or W = 5 and W = -22/4 = -11/2

            2(2)

A measure of length can't be negative, so we reject W = -11/2 in favor of W = 5.

Then, according to the formula for L that we found earlier, L  = 2W + 1, or

L = 2(5) + 1, or L = 11.

Check:  Does L * W result in an area of 55 ft²?  Yes

The length dimension of the rectangle is 11 ft

26

step-by-step explanation:

a

step-by-step explanation:

u take $30 minus $24. the answer/original($30)