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Mathematics, 28.03.2021 19:50 Edith21

F(x)=-\dfrac{1}{2}(x-2)(x+8)f(x)=βˆ’ 2 1 ​ (xβˆ’2)(x+8)

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F(x)=-\dfrac{1}{2}(x-2)(x+8)f(x)=βˆ’ 2 1 ​ (xβˆ’2)(x+8)...
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