Solve x2 + 12x = –11 by completing the square. Which is the solution set of the equation? {–11, –1} {–11, 1} {11, –1} {11, 1} , PLEASE HURRY !! :( THANK YOU!

{–11, –1}

Step-by-step explanation:

hope that helps

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19NBoli

x2

Step-by-step explanation:

x2+12x+11=0

x2+(11+1)x+11=0

x2+11x+1x+11=0

x(x+11)+1(x+11)=0

(x+11)(x+1)=0

either,

x+11=0

x=-11

OR,

x+1=0

x=-1

{-11,-1}

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

answer: b

step-by-step explanation: