A father is 28 years solder than his daughter. In six years, he will be 3 times her age. Find their present ages. Please use an algebraic equation to solve, and show your working. A photo of your working out on paper is also fine as long as I can read it.

father:45

Daughter:17

Step-by-step explanation:

Present

Father (X+28)yrs

Daughter X yrs

After 6 years father will be (X+28)+6= 3x

28+6=3x-x

34=2x

X=17yrs=daughter

Father=28+17=45yrs

answer: answer is c!

ok i got to organize the

3/15 and 12/55

3*

aha

3*4 equals 12 but not

a: no

b:

8/24 12/35

no

gautie

it's c

5/18 = 25/90

5*5=25

18*5 = 90

hope that you!

one more happy customer!

< 3

step-by-step explanation:

step-by-step explanation:

if you meant, "on the way from (3, 2) to (3, 14):

x does not change; y increases by 12.

ensure that you have copied down this problem correctly.   .