A father is 28 years older than his daughter. In six years' time, he will be three times her age. Find their present ages. Please use an algebraic equation to find the answer and show your working out if possible!!

8 and 36

Step-by-step explanation:

let the daughter's age be x then father is x + 28

In 6 years their ages are

x + 6 and x + 28 + 6 = x + 34

Father is 3 times her age , then equation is

x + 34 = 3(x + 6) ← distribute

x + 34 = 3x + 18 ( subtract x from both sides )

34 = 2x + 18 ( subtract 18 from both sides )

16 = 2x ( divide both sides by 2 )

8 = x

Daughter's age is 8 and father's age is 8 + 28 = 36

first option

a function is a relation in which an input is paired with exactly one output.

so, let's find the right answer.

in our first option, our inputs are january, february, and march. the outputs are 30, 28, and 25. each input has it's own output. this is correct!

our second option we know is incorrect, because ms. valverade has two outputs, dogs and cats. this is not a function.

our third option is incorrect as well. the yellow square has two ouputs, the square and the triangle.

lastly, in our fourth option, we see the number 7 two times with a different output. therefore, this is not a function.

remember: each input must be paired with only one output!

1     sepan

2     encuentren

3     tenga

4     hable

5   parezca

6   llegue