Hi i would rly appreciate ur help on this. I need to write these expressions as products: 1. ((a+1)^3)+(x^3)
2. ((y-2)^3)-27
3.((a-b)^3)+b^3
4. (8x^3)+((x-y)^3)
5. (27a^3)-((a-b)^3)
Thank you so much i rly appreciate it

1.)   ((a+1)^3)+(x^3)  = a^3 + 3a^2 + 3a + x^3 + 1

2.)  ((y-2)^3)-27  =   (y^2-y + 7) x ( y - 5 )

3.)   ((a-b)^3)+b^3  = a (a^2 - 3ab + 3b^2 )

4.)   (8x^3)+((x-y)^3)  =  9x^3 -3x^2 y + 3xy^2 - y^3

5.)   (27a^3)-((a-b)^3) = 26a^3 + 3a^2 b - 3ab^2 + b^3

5) factor = (a+b)(a+b)^ 2    if a is squared and if b is cubed and moved over to = 0 then we can find (a+b)(a+b)^2 but in all cases of quadratics you can set (x -1 ) = 1 and (x-1 ) = 1  so they are always positive. Which is the same if they start of negative.

For question 5 we have a factor solved (a+b)(a+b)^ 2

Which means the same as this expansion

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0.84 dang lotta people are looking for this lol or if you round up its 1 but the overall answer to that is 0.84

step-by-step explanation:

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step-by-step explanation:

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