Given this set of data: 132 127 106 140 158 135 129 138 What are the lower outlier limit and the upper outlier limit ? Answers separated by a comma and a space. Ex. 11, 179 * 1 point

(111.5, 155.5)

Step-by-step explanation:

Given the data:

132 127 106 140 158 135 129 138

The Outlier formula :

Lower = Q1 - 1.5(IQR)

Higher = Q3 + 1.5(IQR)

Using a calculator :

Q1 = 128

Median, Q2 = 133.5

Q3 = 139

IQR = Q3 - Q1 = 139 - 128 = 11

Lower = Q1 - 1.5(IQR) = 128 - 1.5(11) = 111.5

Higher = Q3 + 1.5(IQR) = 139 + 1.5(11) = 155.5

(111.5, 155.5)

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation:

circle area = pi * radius^2

if diameter = 10 then radius = 5

circle area = pi * 5^2

circle area = pi * 25

circle area = 78.5398163397 square units

step-by-step explanation: