The ages of the racers in a bicycle motocross race are 14, 22, 20, 25, 26, 17, 21, 30, 27, 25, 14, and 29. The 30-year-old drops out of the race and is replaced with a 15-year-old. How are the mean, median, and mode of the ages affected?

The mean is decreased by 1.25.

The mode  remains the same.

The median is decreased by 2 .

Step-by-step explanation:

Re arranging the data 14, 22, 20, 25, 26, 17, 21, 30, 27, 25, 14, and 29.

Gives

14, 14,17,20,  21, 22, 25,25, 26,  27, 29,30,  

Now the mean = 14, +14,+17, +20, +21,+ 22, +25,+25,+ 26, +  27, +29,+30/12

Mean= 270/12=22.5

The Mode ( the repeated value) = 14,25

Median ( the average of middle value) =  22+25/2= 23.5

When 30 is replaced is by 15

Now the mean = 14, +14, +15,+17, +20, +21,+ 22, +25,+25,+ 26, +  27, +29/12

The  Mean becomes = 255/12=21.25

The Mode ( the repeated value) = 14,25

Median ( the average of the middle value) =  21+22/2= 21.5

The difference between the 2 means  is = 22.5- 21.25= 1.25

The mode  remains the same.

The median is decreased by 2 .

The mean is decreased by 1.25 which is more than 50 % of the value obtained between the ratio of the omitted and added value (30/15=) i.e. 2

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

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step-by-step explanation: