Which equation represents the linear function that is shown on the graph ​

Y = (1/2)x - 2

Step-by-step explanation:

To compose a linear equation, always use the form

Y = Mx + C where C is the y-intercept and M is the gradient.

In this case, pick any 2 points on the graph to solve for M

e.g (8,2) and (6,1)

Gradient = (2 - 1) /(8 -6) given by (y1 - y2) / (x1 - x2) = 1 / 2

Substitute into the form, we get

Y = (1/2)x + C

Now, we use any point again on the graph,

e.g (6,1) and substitute as (x, y) into the above function.

We will get 1 = (6)(0.5) + C

C = -2

Piece them up and u get the full function.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.