If 3 runners has a mean running time of 6.2, 7.4 and.6.9 and had an interquartile range of 1.1, .02 and .08 who would be the fastest runner

The runner with a mean running time of 6.2

Step-by-step explanation:

The value range parameters of the three runners are;

The mean running time of the runner, A = 6.2

The mean running time of the runner, B = 7.4

The mean running time of the runner, C = 6.9

The interquartile range of the runner, A = 1.1

The interquartile range of the runner, B = 0.02

The interquartile range of the runner, C = 0.08

Whereby the number of running times for the 3 runners is large, and with the assumption that distribution of the mean is normal, we have

The mean = The mode of  the data

Therefore, the minimum, and maximum running time of the runners are;

Runner A;

Minimum running time = 6.2 - 1.1 = 5.1

Maximum running time = 6.2 + 1.1 = 7.3

Runner B;

Minimum running time = 7.4 - 0.02 = 7.38

Maximum running time = 7.4 + 0.02 = 7.42

Runner C;

Minimum running time = 6.9 - 0.08 = 6.82

Maximum running time = 6.9 + 0.08 = 6.98

The fastest runner has the lowest running time;

Therefore, the fastest runner is runner A with a mean running time of 6.2  with a minimum running time of 5.1

the required function is .

step-by-step explanation:

from the given table it is noticed that the graph passing through (-3,7), (0,4), (3,1) and (8,-4).

it is a linear function because the value of y is decrease by one as the value of x increase by 1.

the slope of the function is

the slope of the function is -1 and the y-intercept is 4.

the slope intercept form is

where, m is slope and b is y-intercept.

therefore the required function is . the graph of this function is shown below.

answer: 34rtyj,jkhtyetwrhyjeuiejnbhdfknbkguxfrbhkfdbjvkmbd,kvbsd.kxjvbhjnfbgjxdfn

step-by-step explanation: