Aspherical balloon is inflated so that its volume is increasing at the rate of 2 ft3/min. how rapidly is the diameter of the balloon increasing when the diameter is 1.7 feet?

According to the question requirements 

v= 4/3*pi*r^3

dv/dt = 4*pi*r^2*dr/dt

when 
d= 1.7
r= 0.85
and 
dv/dt = 2

2= 4*pi*(0.85)^2*dr/dtthus the the speed of increasing of the balloon's diameter is 
dr/dt = 1/(2pi*(0.85)^2)

=0.2203 ft/min

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