Find the missing dimension of the cone

h=1ft

Step-by-step explanation:

The volume of a cone is:

v=πr^h/3

plug in the values (I am assuming not 1/18π but 1/18×π):

1/18π=  π1/3^2h/3

Get rid of the radius:

1/3^2=1/9

Continue:

π/18= πh/3*1/9= πh/18

Remove the denominators:

π=πh

Divide both sides by π :

h=1

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4

what chart am i supposed to follow?