A boat in calm seas travels in a straight line and ends the trip 10 km east and 29 km south of its original position. Find the distance of the trip to the nearest tenth.

A boat in the calm seas travels in a straight line and ends the trip 22 km west and 53 km north of its original position. To the nearest tenth of a degree, find the direction of the trip.

Assume the start is at (0,0)
The end is at (-22,53).

direction = tan^-1(-53/22) = -67.46
But the angle is in the 2nd Quadrant.
So, direction = -67.46 + 180 = 112.54 degrees

Cheers,
Stan H.

The answer is c. 7 (i think) i’m almost sure though