A researcher plans to conduct a test of hypotheses at the 1% significance level. She designs her study to have a power of 0.90 at a particular alternative value of the parameter of interest. What is the probability that the researcher will commit a Type II error for the particular alternative value of the parameter at which she computed the power

P(Type II error) = 0.1

Step-by-step explanation:

In statistics, the formula for power of a hypothesis is given by;

Power = 1 - P(Type II error)

Where P(Type II error) is the probability of making a Type II error.

We are told that the power is 0.9.

Thus;

0.9 = 1 - P(Type II error)

Making P(Type II error) the subject gives;

P(Type II error) = 1 - 0.9

P(Type II error) = 0.1

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

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