Some one help
3x^2-10x-8​

(3x+2) (x-4)

Step-by-step explanation:

(x - 4)(3x + 2)

Step-by-step explanation:

1.) Use the sum-product pattern

3x^2-10x-8​

3x^2+2x-12x-8

2.) Common factor from the two pairs

3x^2+2x-12x-8

x(3x+2)-4(3x+2)

3.) Rewrite in factor form

x(3x+2)-4(3x+2)

(x - 4)(3x + 2)

Solution

(x - 4)(3x + 2)

the f

last graph i believe

step-by-step explanation:

worked it out i believe

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.