Mathematics, 25.03.2021 02:40 exoticbunnylover123
Solve 2 cos^2 0=-1-sin^2 0 on the interval 0° ≤ θ ≤ 360°.
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Solve 2 cos^2 0=-1-sin^2 0 on the interval 0° ≤ θ ≤ 360°....
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