Round to the nearest 10th if necessary

Step-by-step explanation:

ah they are getting harder.    :/  they didn't give any angles this time. so figure those out first,   super hero math to the rescue  :P oh and the question is just find angle C  soo.

Angles  C + B + A = 180

we can turn the law of cosines around and use it to find the angle, you are given the formula for that as well in the problem.   it's nice of them to not expect you to memorize the formula   I had to :/   your class is going easy on you.   get out the ruler and smack some students ,  prof. Snape   :D :D  My prof. once threw an eraser at one person b/c they fell asleep in class  :D  when it hit him.. b/c it was all full of chalk.. the eraser.. it kinda  "exploded"   and he woke up coughing...  :o    anyway.. back to math  :P

a= 28

b= 17

c = 15

C = arcCos [ (a^2 + b^2 - c^2)  /  (2 * a * b) ]

C = arcCos[ 28^2 + 17^2 - 15^2  / 2*28 *17 ]

C = arcCos[ 784 + 289 -225 / 952 ]

C = arcCos [ 848 / 952 ]

C = arcCos [0.8907563]

C = 27.03 °

rounded to nearest 10th then is

C = 27.0 °

:)  

btw, does 27 seem right?   to me it does b/c that angle is small

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.