PLEASE HELP ASAP WILL GIVE BRAINLIEST Question 1 of 10 Which point lies on the line described by the equation below?
y + 4 = 4(x-3)
A. (1,-11)
B. (3,-4)
C. (1,11)
D. (0,0)
E. (-2,3)
O F. (2,9)

(3, -4)

Step.

line or a linear equation graph

step-by-step explanation:

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this