4. Line m passes through point (5, -8) and has a slope-3. What is the equation for the line in point-slope form? Oy - 8 = 3(x - 5)
Oy-8= 3x – 15
Oy+8 = -3(x - 5)
O y=-3x + 7

i got 86 for this

hope this !

if you need an explanation just ask

need more info

step-by-step explanation:

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240

the answer is 1 becuz if it were 1.0 that would rip apart the entire so ya. : )

~potato.

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