(3−k)x−4(3−k)y=−27 In the given linear equation, k is a constant and k≠3. When graphed in the xy-plane, what is the slope of the line?

it would open into a square depending on the type of envelope i’m not sure about the second part

vertical=18cm horizontal=18cm hypotenuse=25.5

step-by-step explanation:

answer: (-8,4) are the coordinates of a

step-by-step explanation:

let the side of square abcd is x .

thus the area of square abcd is .

now, by the diagram area of triangle ead= 1/2 × ea × ad = 1/2 × ea × x

( because ad is the side of square)

and, according to the question,

the areas of square abcd and right ead are equal.

⇒

⇒ea=2x

thus, ea: ab=2: 1

therefore, point a divides line segment eb into the ratio 2: 1.

⇒ by sectional formula coordinates of a are,

=

=

=(-8, 4)

thus the coordinates of a are (-8,4)