A square has a diagonal of 44in. I want to frame the picture, how many inches of frame do I need

The square has a 44-inch diagonal.

The pythagorean equation must be used to obtain the hand.

Diagonal (d) ^ 2 = side^2 + side ^ 2

Diagonal (d) ^ 2 = 2side (s)^2

d^2 = 2s^2

44^2 = 2s^2

1936 = 2s^2

2s^2 = 1936

s^2 = 968

s = 31.11 inches

The length of the side is around 31 inches

Perimeter = 4*s

Perimeter = 4 * 31

Perimeter = 124 inches

As a result, you will need a total of 124 inches to frame the rectangle.

Hope this helps you!!

the balance is found at the link

step-by-step explanation:

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: