The results that follow were obtained from an analysis of data obtained in a study to assess the relationship between percent increase in yield (Y) and base saturation (x1, pounds/acre), phosphate saturation (x2, BEC%), and soil pH (x3). Fifteen responses were analyzed in the study. The least-squares equation and other useful information follow. y^=38.83-0.0092x1-0.92x2-11.56x3, Syy=10965.46, SSE=1107.01

a. Is there sufficient evidence that, with all independent variables in the model, β2 < 0? Test at the α = .05 level of significance.
b. Give a 95% confidence interval for the mean percent increase in yield if x1 = 914, x2 = 65 and x3 = 6.

a. yes there is enough evidence

B. -22.83, 102.79

Step-by-step explanation:

H0: B2 >= 0

H1: B2 < 0

Alpha = 0.05

T critical is calculated to be -1.79

If t is less than -1.79 we reject the null hypothesis

Test statistic

S = √1107.01/15-3-1

= 10.032

T stat = -0.92 - 0/10.032√0.00081

= -3.222

-3.222 is less than -1.79

So we Reject the null hypothesis and conclude that enough evidence exists that B2<0

B. At 95% confidence

38.83 - 0.0092x1 - 0.92x2 + 11.56x3

= 38.83 - 0.0092x914 - 0.92x65 + 11.56x6

= 38.83 - 8.4088 - 59.8 + 69.36

= 39.98

39.98-2.2*28.55,39.85+2.2*28.55

= 39.98 - 62.81, 39.98 + 62.81

= -22.83, 102.79

15%

step-by-step explanation:

use the table and count the number of guesses that has two correct answers.

the following are two correct answers

10010, 01100, 11000

a total of 3 numbers having 2 correct guesses out of 20 questions.

probability of getting 2 correct guesses = the number of questions getting 2 correct answers / total number of questions.

= 3/20

to convert it into percent multiply by 100, we get

= 3/20 * 100

= 15%

the answer is 15%

you.