6a+4b−66, a, plus, 4, b, minus, 6 when a=1a=1a, equals, 1 and b=3b=3b, equals, 3.

The answer is 12.

Step-by-step explanation:

We need to find the value of the given expression 6a+4b−6 when a = 1 and b = 3

Put a = 1 and b = 3 in the above expression.

6a+4b−6 = 6(1) +4(3) -6

= 6+12-6

= 12

So, the value of the given expression is equal to 12.

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

24 units

step-by-step explanation: