Given f(x) = 3 (x+4)^2 -6, select the 4 statements that are correct about the graph of the function. A: The Vertex is at 4, -6
B: The Vertex is at -4, -6
C: The axis of symmetry is x = -4
D: The axis of symmetry is x = 4
E: The minimum is -4
F: The minimum is -6
G: The range is y is greater than equal to -6
H: The range is y is less than equal to -6

might be the correct answer will be question number 2

place r′ so that qr′ is parallel to the tangent.

now we get that ∠r′py=∠pr′q, where y is on the tangent, on the opposite side of p from x.

also, because of the symmetry, ∠r′py=∠qpx.

finally, note that no matter where we place r, as long as it's on the correct arc, we have ∠prq=∠pr′q.

stringing all these equalities together, we end up with ∠prq=∠qpx.

this picture will show how its going to look like.

hope this by jack monhen

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