What is the equation of a line that passes through the points (3,6) and (8, 4)? 3
Oy= 22
o - -
o v x 27
0 - 22/x - 29
oy- - 2 x + 38

In the equation y=mx+b, 'm' is the slope of the line and 'b' is the y-intercept.  

First, you should find the slope of the line.  To do this, use the equation M=y2-y1/x2-x1.  Using the two given points (3,6) and (8,4), you can solve for M.  

M=4-6/8-3

M=-2/5 (-0.4 in decimal form)

Now, your equation is y=-0.4x+b

Next you must solve for b to find the y-intercept.  You can do this by subbing one of the given points in for x and y.  

Using the point (3,6):

y=-0.4x+b

6=-0.4(3)+b

6=-1.2+b

Isolate b:

6+1.2=b

b=7.2

And now you have the equation of the line!

y=-0.4x+7.2 (IN FRACTION FORM: y=-2/5x+36/5)

Step-by-step explanation:

here is the

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