A helicopter flew north 325 meters and then flew east 500 meters. How far is the helicopter from its starting point?

596.34m approx

Step-by-step explanation:

Given data

Let the Starting point be x

A helicopter flew north 325 meters from x

Then flew east 500 meters

Let us apply the Pythagoras theorem to solve for the resultant which is the distance from the starting position

x^2= 325^2+500^2

x^2=105625+250000

x^2= 355625

x= √355625

x=596.34m

Hence the distance from the starting point is 596.34m approx

answer: plz put a pic in so i can answer it

step-by-step explanation:

rotation point l

step-by-step explanation: