The height of an overhand volleyball serve can be modeled as h=-16t^2+20t+6. After how many seconds is the ball 11 feet.

0.9043secs and 0.3456secs

Step-by-step explanation:

Given the height of an overhand volleyball modeled as h=-16t^2+20t+6.

If the height is 11feet, then;

11 = -16t^2+20t+6.

-16t^2+20t+6 - 11 = 0

-16t^2+20t-5 = 0

Multiply thriugh by -1

16t^2-20t+5 = 0

Factorize

t = 20±√20²-4(16)(5)/2(16)

t = 20 ±√400-320/32

t = 20 ±√80/32

t = 20 ±4√5/32

t = 20±8.94/32

t = 28.94/32 and 11.06/32

t = 0.9043 and 0.3456

Hence the required time are 0.9043secs and 0.3456secs

1)is not similar since corresponding sides are not in the same ratio

2)are similar since corresponding sides are in the same ratio and corresponding angles are equal

hope it will

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step-by-step explanation:

sorry no step by step