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Mathematics, 23.03.2021 16:30 madiballet125

Solve for ppp. -5\left(p+\dfrac35\right) = -4βˆ’5(p+ 5 3 ​ )=βˆ’4minus, 5, left parenthesis, p, plus, start fraction, 3, divided by, 5, end fraction, right parenthesis, equals, minus, 4

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Solve for ppp. -5\left(p+\dfrac35\right) = -4βˆ’5(p+ 5 3 ​ )=βˆ’4minus, 5, left parenthesis, p, plus, st...
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