If each data is increased by a constant K then find it's mean ?? answer fast pleas​

The mean is also increased by the constant k.

Step-by-step explanation:

Suppose that we have the set of N elements

{x₁, x₂, x₃, ..., xₙ}

The mean of this set is:

M = (x₁ + x₂ + x₃ + ... + xₙ)/N

Now if we increase each element of our set by a constant K, then our new set is:

{ (x₁ + k), (x₂ + k), ..., (xₙ + k)}

The mean of this set is:

M' = ( (x₁ + k) + (x₂ + k) + ... + (xₙ + k))/N

M' = (x₁ + x₂ + ... + xₙ + N*k)/N

We can rewrite this as:

M' = (x₁ + x₂ + ... + xₙ)/N + (k*N)/N

and  (x₁ + x₂ + ... + xₙ)/N was the original mean, then:

M' = M + (k*N)/N

M' = M + k

Then if we increase all the elements by a constant k, the mean is also increased by the same constant k.

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

homozygous. one is homozygous, while two is heterozygous.