Find the area of the figure if needed round to the nearest tenth isosceles trapezoid

The image of the isosceles trapezoid is missing, so i have attached it.

A = 18 Sq.ft

Step-by-step explanation:

From the image attached, it is a trapezium.

Formula for area of a trapezium is;

A = ½(a + b)h

Where;

a and b are the parallel sides

h is height.

From the image attached;

a = 4ft

b = 8 ft

h = 3 ft

Thus;

A = ½(4 + 8)×3

A = ½ × 12 × 3

A = 18 Sq.ft

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°