In the diagram below, AB = BD = BC, and mZA = 24°. Find
mZC.

m∠C = 66°

Step-by-step explanation:

Since AB = BD, it means this triangle is an Isosceles triangle and as such;

∠BAD = ∠BDA = 24°

Thus, since sum of angles in a triangle is 180,then;

∠ABD = 180 - (24 + 24)

∠ABD = 180 - 48

∠ABD = 132°

We are told that BC = BD.

Thus, ∆BDC is an Isosceles triangle whereby ∠BCD = ∠BDC

Now, in triangles, we know that an exterior angle is equal to the sum of two opposite interior angles.

Thus;

132 = ∠BCD + ∠BDC

Since ∠BCD = ∠BDC, then

∠BCD = ∠BDC = 132/2

∠BCD = ∠BDC = 66°

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step-by-step explanation: