Find the point on X axis which is equidistant from A(-3,4) and
B (1,-4)​

the coordinates of point which is present on x axis is (x, 0)

let P(x, 0) is equidistant point from A(-3, 4) and B(1, -4)

PA=PB

squaring on both sides

PA^2=PB^2

[x-(-3) ]+(0-4) =(x-1) +[0-(-4) ]

x+3) +16=x^2-2x+1+16

x^2+6x+9+16=x^2-2x+1+16

6x+9=-2x+1

6x+2x=9-1

8x=8

x=8/8

x=1

Step-by-step explanation:

what are you doing do you need examples of variable questions?

step-by-step explanation:

5a-1=9               bring the one over the =

5a=10                     divide by your variable

a=2

brainliest? ?

here try this one

3a-24=0