Astore had 175 cell phones in the month of january. every month, 10% of the cell phones were sold and 10 new cell phones were stocked in the store. which recursive function best represents the number of cell phones in the store f(n) after n months? f(n) = 175 − 0.9 × f(n − 1) + 10, f(0) = 175, n > 0 f(n) = 0.1 × f(n − 1) + 10, f(0) = 175, n > 0 f(n) = 175 + 0.9 × f(n − 1) + 10, f(0) = 175, n > 0 f(n) = 0.9 × f(n − 1) + 10, f(0) = 175, n > 0
99 points

f(n) = 0.9 × f(n − 1) + 10,   f(0) = 175,  n > 0

Step-by-step explanation:

Given: A store had 175 cell phones in the month of January.

Every month, 10% of the cell phones were sold and 10 new cell phones were stocked in the store.

Let n be the number of months

Then when n=0

f(0)=175

After first month , n=1

The number of cell phone in store=

Thus

Similarly we can do till n months, we get

f(n)=0.9×f(n−1)+10, f(0) = 175, n > 0

Step-by-step explanation:

Given :

A store had 175 cell phones in the month of January.

Every month, 10% of the cell phones were sold and 10 new cell phones were stocked in the store.  

To Find:

Which recursive function best represents the number of cell phones in the store f(n) after n months?

Solution:

Let n be the number of months  

So, when n=0

f(0)=175

Now, after 1 month i.e. At n=1

Now we are given that Every month, 10% of the cell phones were sold and 10 new cell phones were stocked in the store.

The number of cell phone in store after 1 month =

Thus  

Similarly we can do till n months,Thus , we get

Hence Option 4 is correct.

76%

step-by-step explanation:

24% are dogs and the remaining is 76% because 100-24=76

translate k to n and reflect across the line containing jk.