At 4 PM, the level of the water in the lake was 10 feet. At 8 PM, the level of the water was 2 feet. Determine the constant rate of change of the water.

Step-by-step explanation:

Level of water at 4 PM is 10 feet.

Level of water at 8 PM is 2 feet.

Time duration in which water level is measured is

The change of the level of water in the given time duration is

The rate of change would be

The constant rate of change of the water is .

The minus sign indicates that the water level is reducing.

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.