ALGEBRA 1 ! CAN SOMEONE PLEASE MAKE THESE EQUAL 0 OR MAKE IT THE REAL EQUATION PLS

1: 2x^2+3x=9

2: 2x^2+5=-11

3: 3x^2=+2x+5

4: 4x^2+6x+2=0

5: 25x^2+30=-5

Step-by-step explanation:

1.

2x^2+3x -9 = 0

Factor:

(2x-3)(x+3) = 0

x= 3/2 and x = -3

2.

2x^2+5 = -11

2x^2 = - 16

x^2 = -8

x has no value in this equation as you get imaginary values.

3.

3x^2 - 2x - 5 = 0

Factor:

(x+1)(3x-5) = 0

x = -1 and x = 5/3

4.

4x^2+6x+2 = 0

Divide by 2

2x^2 + 3x + 1 = 0

Factor

(2x + 1) (x + 1) = 0

x = -1/2 and x = -1

5.

25x^2 = -35

x has no value in this equation as you get imaginary values.

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m

well the answer to that is xoxoxo

step-by-step explanation: