Solving Systems of Equations by Substitution 1. y = 6x − 11
2. −2x − 3y = −7
3. y = −3x + 5
4. 5x − 4y = −3
5. y = −2
6. 4x − 3y = 18
7. −4x + y = 6
8. −5x − y = 21
9. 2x − 3y = −1
10. y = x − 1
11. −3x − 3y = 3
12. y = −5x − 17
13. y = 5x − 7
14. −3x − 2y = −12
15. −7x − 2y = −13
16. x − 2y = 11

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

that one look

step-by-step explanation: