Can u guys please answer this question. This is extremely urgent The cross-sections of the solids are sectors. Find the surface area, rounding your answer to 1 decimal place.

The total surface area of the figure is approximately 10.2 m²

Step-by-step explanation:

The dimensions of the solid are;

The shape of the solid = An half cylinder

The diameter of the cylinder, D = 1.6 m

The length of the cylinder, l = 2 m

The surface area of the curved part of the solid = π × D × l ÷ 2

Therefore;

The surface area of the curved part of the solid = π × (1.6 m) × 2 m/2 ≈ 5.03 m²

The area of the curved surface, V = 5.03 m²

The area of the rectangular top, A = 1.6 m × 2 m = 3.2 m²

The area surface of the semi-circular sides of the figure = 2 × π·D²/4 ÷ 2

Therefore;

The area surface of the semi-circular sides of the figure = 2 ×π × (1.6 m)²/4 ÷ 2 ≈ 2.01 m²

The total surface area of the figure, A = 5.03 m² + 3.2 m² + 2.01 m² = 10.24 m²

The total surface area of the figure ≈ 10.2 m² (rounding to 1 decimal place)

c. prove the lengths are the same.

step-by-step explanation:

you need to prove the segments are congruent. congruent segments have the same length. find the lengths of the segments using the distance formula, and compare them.

answer: c. prove the lengths are the same.