15. (4 pts.) A weight is attached to the end of a frictionless spring, pulled down to extend the spring, and then released. Let d be the distance of the weight above
the floor at time I, where d is in centimeters and is in seconds. The distance
varies sinusoidally over time. A stopwatch reads 0.0 seconds when the weight is at
it's low point of Il centimeters above the floor. It's first high point 42 centimeters
above the floor occurs at 1.2 seconds. Write a trigonometric equation to express
d in terms of t.

x=half

step-by-step explanation:

2160ft3

step-by-step explanation:

the degrees would remain the same ( the number to the left of the decimal point.

the multiply the decimal by 60 to get the minutes and use the numbers to the left of the decimal point.

then multiply the decimal portion of that by 60 for the seconds and round off as needed.

39 .956652

the 39 remains the degrees.

the minutes = 0.956652 x 60 = 57.39912

the minutes = 57

the seconds = 0.39912 x 60 = 23.95 = 24 ( rounded to nearest tenth)

so 39.956652 = 39 degrees, 57 minutes and 24 seconds

-75.159809

the -75 remains the degrees

the minutes = 0.159809 x 60 = 9.58854

the minutes = 9

the seconds = 0.58854 x 60 = 35.31, rounded to nearest tenth = 35.3 seconds

so -75.159809 = -75 degrees, 9 minutes and 35.3 seconds.

the first coordinate is north or south, since it it positive it is north.

the second number is east or west, because it is negative it is west.

39 degrees, 57 minutes and 24 seconds n

-75 degrees, 9 minutes and 35.3 seconds w

no

step-by-step explanation: