Solve these simultaneous equations: 3. 5x – 3y = 15 4x 3y = 6

2x + 5y = 26 4x + 3y = 24

3x + 3y = 39 2x - 3y = - 2

1) We have the system:

5*x - 3*y = 15

4*x + 3*y = 6

To solve this, we first need to isolate one of the variables in one of the equations, let's isolate x in the first equation:

x = 15/5 + (3/5)*y = 3 + (3/5)*y

Now we can replace this in the other equation to get:

4*( 3 + (3/5)*y) + 3*y = 6

and solve this for y.

12 + (12/5)*y  + 3*y = 6

(12/5 + 3)*y = 6 - 12 = -6

(12/5 + 15/5)*y = -6

(27/5)*y = -6

y = -6*(5/27) = 1.11

Now we can replace this in the equation:

x = 3 + (3/5)*y

To get the value of x.

x = 3 + (3/5)*1.11 = 3.67

Then the solution of this system is the point (3.67, 1.11)

2) Now we have the system:

2*x + 5*y = 26

4*x + 3*y = 24

The solution method is the same as before:

x = 26/2 - (5/2)*y = 13 - (5/2)*y

Now we replace this in the other equation:

4*( 13 - (5/2)*y) + 3*y = 24

52 - 10*y + 3*y = 24

52 - 7*y = 24

52 - 24 = 7*y

28 = 7*y

28/7 = y

4 = y

now we replace this in the equatio:

x = 13 - (5/2)*y

x = 13 - (5/2)*4 = 13 - 10 = 3

The solution of this sytem is (3, 4)

3) Now we have the system:

3*x + 3*y = 39

2*x - 3*y = -2

first we isolate x in the first equation:

x = 39/3 - 3*y/3 = 13 - y

Now we can replace this in the other equation:

2*(13 - y) - 3*y = -2

26 - 2*y - 3*y = -2

26 - 5*y = -2

26 + 2 = 5*y

28 = 5*y

28/5 = y = 5.6

Now we can replace this in the equation:

x = 13 - y

To get the x-value

x = 13 - 5.6 = 7.4

Then the solution for this system is (7.4, 5.6)

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