Jack and Jill are 432 meters apart, but are walking towards each other. Joe walks at a pace of 2 meters per second, while Jill walks at a pace of 3 meters per second. After how many seconds will they meet up?

86.4 seconds.

Step-by-step explanation:

Given that Jack and Jill are 432 meters apart, but are walking towards each other, and Joe walks at a pace of 2 meters per second, while Jill walks at a pace of 3 meters per second, to determine after how many seconds will they meet up, the following calculation must be performed:

432 / (3 + 2) = X

432/5 = X

86.4 = X

So, Jack and Jill will meet after 86.4 seconds.

for b its (t) and c its (d)

step-by-step explanation:

step-by-step explanation:

left be aligning the decimal points is required to not required see the number of digits to the right