A bag contains 6 red marbles, 5 blue marbles and 8 green marbles. If three marbles are drawn out of the bag, what is the probability, to the nearest 10th of a percent, that all three marbles drawn will be green?​

5.8%

Step-by-step explanation:

In this situation there is no replacement so we have to mulitply the probablilty of the first,second, and third marble being green. First marble has a 8/19 probablilty of being selected because 19 total marbles in the bag and 8 green marbles. the next marble will have a 7/18 probabililty because now only 18 marble are in the bag and we are assuming we selected a green marble on our first draw. Same thing with the last green marble it would be 6/17 because there would be 17 marbles in the bag and 6 green ones left assuming we got the first 2

so 8/19*7/18*6/17=

56/969=

0.05779

5.77%

5.8%

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

a. turk and mcalister

b. howard, mission, and market

c. yes. since streets end some do not cross yet are not parallel to others. example: mcalister and 5th

step-by-step explanation:

parallel lines are lines which do not intersect ever and look a lot like railroad tracks. turk, mcalister and golden gate are examples of these.

intersect are streets which cross each other and a car on one can reach the other. howard, mission, and market intersect with 6th.

skew lines are lines which neither intersect nor are parallel. these lines exist here because some streets end and never intersect another like mcalister and 5th.