I'm awarding 20 points for an answer! A ball is thrown into the air with an initial upward velocity of 48 ft/s. It height h in feet after t seconds is given by the function h (t)=-16t^2+48t+4.

What is the ball's maximum height?

40 feet (after 1.5 seconds).

Step-by-step explanation:

The height h of the ball after t seconds is modeled by the function:

And we want to determine the ball's maximum height.

Since the given function is a quadratic, the maximum height occurs at the vertex point.

For quadratics, the vertex point is given by the formulas:

In this case, a = -16, b = 48, and c = 4.

Therefore, the t-coordinate at which the vertex occurs is:

So, the maximum height occurs after 1.5 seconds.

Then the maximum height will be:

So, the maximum of the ball is 40 feet (after 1.5 seconds).

step-by-step explanation:

circumference divided by 3.141592654 then timesthe radius twice

answer: i feel you honey.

step-by-step explanation: